The reaction of sulfuric acid (h2so4) with potassium hydroxide (koh) is described by the equation below. suppose 0.05 l of koh with unknown concentration is placed in a flask with bromthymol blue indicator. a solution of 0.10 m h2so4 is dripped into the koh solution. after exactly 0.033 l of h2so4 is added, the indicator changes from blue to yellow. what is the concentration of the koh.
h2so4+> k2so4+2h2o
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The reaction of sulfuric acid (h2so4) with potassium hydroxide (koh) is described by the equation be...
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