What mass of iron is needed to react with sulfur in order to produce 96 grams of iron (|||) sulfide according to the following equation?
2fe+3s—> fe2s3

51.57 g.

Explanation:

n = mas/molar mass = (96.0 g)/(207.9 g/mol) = 0.46 mol.

Using cross multiplication we can get the no. of moles of Fe that isn eeded to produce 0.46 mol of Fe₂S₃:

2.0 moles of Fe produces → 1.0 mol of Fe₂S₃.

??? moles of Fe produces → 0.46 mol of Fe₂S₃.

∴ The no. of moles of Fe needed = (2.0 mol)(0.46 mol)/(1.0 mol) = 0.92 mol.

mass = no. of moles x molar mass = (0.92 mol)(55.845 g/mol) = 51.57 g.

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the answer is minerals.