Can u me find the empirical formula for question 1

FeO.

Explanation:

Firstly, we need to calculate the no. of moles of Fe and O in the sample:

No. of moles of Fe = mass/atomic mass = (11.2 g)/(55.845 g/mol) = 0.2 mol.

No. of moles of O = mass/atomic mass = (3.2 g)/(16.0 g/mol) = 0.2 mol.

Fe and O have the same no. of moles:

∴ The mole ratio of Fe: O is (1: 1).

∴ The empirical formula of the oxide is: FeO.

ill try to . no promises tho.

explanation: