If you combine 270.0 ml of water at 25.00 â°c and 100.0 ml of water at 95.0 â°c, what is the final temperature of the mixture? use 1.00 g/ml as the density of water.

43.92 °C.

Explanation:

The amount of heat released by hot water = the amount of heat absorbed by cold water.

The amount of heat released to or absorbed by water (Q) = m.c.ΔT.

where, Q is the amount of heat released to or absorbed by water.

m is the mass of water.

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T).

Since, d of water = 1.00 g/mL.

the mass of cold water at 25.0 °C = d.V = (1.00 g/mL)(270.0 mL) = 270.0 g.

the mass of warm water at 95.0 °C = d.V = (1.00 g/mL)(100.0 mL) = 100.0 g.

Q released by warm water = Q absorbed by cold water.

- (m.c.ΔT)released by warm water = (m.c.ΔT)absorbed by cold water.

Since c is the same so,

- (m.ΔT)released by warm water = (m.ΔT)absorbed by cold water.

- [(100 g)(final T - 95.0 °C)] = (270 g)(final T - 25.0 °C).

- 100 final T + 9500 = 270 final T - 6750.

270 final T + 100 final T = 9500 + 6750

370 final T = 16250.

∴ final T = 16250/370 = 43.92 °C.

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.