Me!

a total of 25.0 ml of 0.150 m potassium hydroxide (koh) was required to neutralize 15.0 ml of sulfuric acid (h2so4) of unknown concentration. what is the concentration of the sulfuric acid? pls fill out the table a million!

The neutralization reaction is expressed as:

2KOH + H2SO4 = K2SO4 + 2H2O

We are given the volume and the concentration of the KOH that is used in the reaction. We use this and the relations from the reaction to determine the concentration of the acid.

0.150 mol KOH / L ( .025 L ) ( 1 mol H2SO4 / 2 mol KOH ) = 0.00188 mol H2SO4

Concentration of acid = 0.00188 mol / .015 = 0.125 M of sulfuric acid

hey Hanna .  

do you remember me?

im turkish

I guess you lived in western karolina

Was your name hanna or allecia or alex?

have your rabbits grown?

Explanation:

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)