How many moles of potassium hydroxide are needed to completely react with 1.73 miles of aluminum sulfate according to the following equation al2(so4)3+6koh=2al(oh)3+3k2so4

The answer is: 10.39 moles of potassium hydroxide (KOH) are needed to completely react with 1.73 moles of aluminum sulfate.

Since the equation is already balanced, we can calculate how many moles of potassium hydroxide are needed.

We must remember that in every chemical reaction, the mass is conserved, it means that the total mass of the reactants is equal to the total mass of the products.

So, from the equation, we can know that 1 mole of aluminum sulfate reacts with 6 moles of potassium, so if we need to know how many moles of hydroxide are needed to react with 1.73 moles of aluminum sulfate, we can write the following relation:

So, 10.39 moles of potassium hydroxide (KOH) are needed to completely react with 1.73 moles of aluminum sulfate.

Have a nice day!

yes, water is wet, just as it makes other things wet, it is wet itself, kinda like ice, when ice is in water, the ice makes water cold, and ice is cold, therefore with that example, water is wet