What is the molarity of the diluted solution when each of the following solutions is diluted to the given final volume? (a) 1.00 l of a 0.250-m solution of fe(no3)3 is diluted to a final volume of 2.00 l (b) 0.5000 l of a 0.1222-m solution of c3h7oh is diluted to a final volume of 1.250 l (c) 2.35 l of a 0.350-m solution of h3po4 is diluted to a final volume of 4.00 l (d) 22.50 ml of a 0.025-m solution of c12h22o11 is diluted to 100.0 ml

a) 0.125 M.

b) 0.04888 M.

c) 0.2056 M.

d) 5.625 x 10⁻³ M.

Explanation:

(MV)before dilution = (MV)after dilution

(a) 1.00 L of a 0.250 M solution of Fe(NO₃)₃ is diluted to a final volume of 2.00 L.

∵ (MV)before dilution of Fe(NO₃)₃ = (MV)after dilution of Fe(NO₃)₃

M before dilution = 0.250 M, V before dilution = 1.00 L.

M after dilution = ??? M, V after dilution = 2.00 L.

∵ (MV)before dilution of Fe(NO₃)₃ = (MV)after dilution of Fe(NO₃)₃

∴ (0.250 M)(1.00 L) = (M after dilution of Fe(NO₃)₃)(2.00 L)

∴ M after dilution of Fe(NO₃)₃ = (0.250 M)(1.00 L)/(2.00 L) = 0.125 M.

(b) 0.5000 L of a 0.1222 M solution of C₃H₇OH is diluted to a final volume of 1.250 L.

∵ (MV)before dilution of C₃H₇OH = (MV)after dilution of C₃H₇OH

M before dilution = 0.1222 M, V before dilution = 0.500 L.

M after dilution = ??? M, V after dilution = 1.250 L.

∵ (MV)before dilution of C₃H₇OH = (MV)after dilution of C₃H₇OH

∴ (0.1222 M)(0.500 L) = (M after dilution of C₃H₇OH)(1.250 L)

∴ M after dilution of C₃H₇OH = (0.1222 M)(0.500 L)/(1.250 L) = 0.04888 M.

(c) 2.35 L of a 0.350 M solution of H₃PO₄ is diluted to a final volume of 4.00 L.

∵ (MV)before dilution of H₃PO₄ = (MV)after dilution of H₃PO₄

M before dilution = 0.350 M, V before dilution = 2.35 L.

M after dilution = ??? M, V after dilution = 4.00 L.

∵ (MV)before dilution of H₃PO₄ = (MV)after dilution of H₃PO₄

∴ (0.350 M)(2.35 L) = (M after dilution of H₃PO₄)(4.00 L)

∴ M after dilution of H₃PO₄ = (0.350 M)(2.35 L)/(4.00 L) = 0.2056 M.

(d) 22.50 mL of a 0.025 M solution of C₁₂H₂₂O₁₁ is diluted to 100.0 mL.

∵ (MV)before dilution of C₁₂H₂₂O₁₁ = (MV)after dilution of C₁₂H₂₂O₁₁

M before dilution = 0.025 M, V before dilution = 22.50 mL.

M after dilution = ??? M, V after dilution = 100.0 mL.

∵ (MV)before dilution of C₁₂H₂₂O₁₁ = (MV)after dilution of C₁₂H₂₂O₁₁

∴ (0.025 M)(22.50 mL) = (M after dilution of C₁₂H₂₂O₁₁)(100.0 mL)

∴ M after dilution of C₁₂H₂₂O₁₁ = (0.025 M)(22.50 mL)/(100.0 L) = 5.625 x 10⁻³ M.

the answer is 1 i believe

catya your not at all which answer i've seen you do this on another question!