A2.0 molal sugar solution has approximately the same freezing point as 1.0 molal solution of 1) cacl2 2) ch3cooh 3) nacl 4) c2h5oh

3) NaCl.

Explanation:

∵ ΔTf = iKf.m

where, i is the van 't Hoff factor.

Kf is the molal depression freezing constant.

m is the molality of the solute.

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.

So, for sugar: i = 1.

∴ ΔTf for sugar = iKf.m = (1)(Kf)(2.0 m) = 2 Kf.

For NaCl, it is electrolyte compound which dissociates to Na⁺ and Cl⁻.

So, i for NaCl = 2.

∴ ΔTf for NaCl = iKf.m = (2)(Kf)(1.0 m) = 2 Kf.

So, the right choice is: 3) NaCl.

answer: h+ its less than oh

explanation:

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: