How many grams of nano3 are required to saturate 200 grams of water at 10 degrees celsius

162.0 g.

Explanation:

The solubility of NaNO₃ in 100.0 g of water at 10.0°C is 81.0 g/ 100 g water.

Using cross multiplication:

81.0 g of NaNO₃ form saturated solution at 10.0°C in → 100.0 g of water.

g of NaNO₃ form saturated solution at 10.0°C in → 200.0 g of water.

∴ The grams of NaNO₃ form saturated solution at 10.0°C in 200.0 g of water = (81.0 g)(200.0 g)/(100.0 g) = 162.0 g.

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.