Brainliesttt !me : )

when methane, ch4, is combusted, it produces carbon dioxide, co2, according to the unbalanced equation: ch4 + o2 → co2 + h2o.

write the balanced equation for this reaction, and explain how it is possible for 10 grams of methane fuel to burn and emit 27 grams of carbon dioxide. discuss whether or not this reaction obeys the law of conservation of mass.

balanced equation is

CH4 + 2O2 -> CO2 + 2H2O

moles of methane = mass ÷ MR

10 ÷16 = 5/8 moles

moles for CO2 are the same because the ratio is 1:1

mass of CO2 = moles × MR

= 5/8 × 44

= 220/8

= 27.5grams

the answer is d   for sure : )

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explanation: