Find the moles of each product formed when 3.40 mol c3h7oh reacts with oxygen

the balanced equation for the combustion reaction is as follows

2C₃H₇OH + 9O₂ ---> 6CO₂ + 8H₂O

we are assuming that O₂ is in excess and C₃H₇OH is the limiting reactant

therefore the amount of product formed depends on the amount of C₃H₇OH present.

we have to find the number of CO₂ and H₂O moles formed

molar ratio of C₃H₇OH to CO₂ is 2:6 simplified to 1:3

when 1 mol of C₃H₇OH reacts - 3 mol of CO₂ is formed

therefore when 3.40 mol of C₃H₇OH reacts - 3 x 3.40 = 10.2 mol of CO₂ is formed

molar ratio of C₃H₇OH to H₂O is 2:8 simplified to 1:4

when 1 mol of C₃H₇OH reacts - 4 mol of H₂O is formed

therefore when 3.40 mol of C₃H₇OH reacts - 4 x 3.40 = 13.6 mol of H₂O is formed

10.2 mol of CO₂ and 13.6 mol of H₂O is formed

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