Calculate the molarity of a solution in which 212.5g of nano3 are contained in 3.0 liters of solution.

Molarity's formula is: moles solute/liters solution.

In this question, we are given grams of solute so we have to convert that to moles.

NaNO3 has a molar mass of 84.9947g/mol. Here we begin with the given 212.5g and multiplying it by 1mol/84.9947g because the grams have to cancel out to give moles.

Now that we have moles of solute, we just plug it into the formula.

2.5 mols NaNO3/3L solution=0.8333 M of solution

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'

the answer is true. hope it .