5. an aluminum (aℓ) cylinder is 10.0 cm in length and has a radius of 2.5 mm. if the mass of a single aℓ atom is 4.48 x 10-23 g, calculate the number of aℓ atoms present in the cylinder. the density of aluminum is 2.70 g/cm3. (volume of a cylinder = π r2 ℓ and π=3.14)

= 1.183 × 10^25 atoms

Volume of  a cylinder is given by the formula;

πr²h , where r is the radius, and h is the height or length.

Volume = 3.14 × 2.5² × 10

             = 196.25  cm³

But density = 2.7 g/cm³

Therefore;

Mass = volume × density

        = 196.25 × 2.7

        = 529.875 g

But; 1 atom =  4.48 x 10-23 g

Therefore;

Number of atoms = 529.875 g / 4.48 x 10-23 g

                              = 1.183 × 10^25 atoms

? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.