At 60°c, the ion-product constant of water, kw, is 9.25 × 10–14 . what is the ph of pure water at 60°c ?

6.517.

Explanation:

Kw = [H₃O⁺][OH⁻] = 9.25 x 10⁻¹⁴.

∵ [H₃O⁺] = [OH⁻].

∴ [H₃O⁺]² = 9.25 x 10⁻¹⁴.

∴ [H₃O⁺] = √(9.25 x 10⁻¹⁴) = 3.041 x 10⁻⁷ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(3.041 x 10⁻⁷) = 6.517.

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