A2.50 l sample of a gas at 1.00 atm is subjected to 1.25 atm of pressure at constant temperature. what is the new volume of the gas?

2.0 L.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

P₁V₁ = P₂V₂

P₁ = 1.0 atm, V₁ = 2.5 L.

P₂ = 1,25 atm, V₂ = ??? L.

∴ V₂ = P₁V₁/P₂ = (1.0 atm)(2.5 L)/(1.25 atm) = 2.0 L.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer