What means of no2 is contained in a 13.0l tank at 464 kpa and 112 celsius 289g 191 g 86.5 g 1.88 g

= 86.5 g

Explanation:

Using the equation;

PV = n RT

where P is the pressure, 464 kpa or 4.58 atm

V is the volume , 13.0 l

n is the number of moles

R is the ideal gas constant , 0.0821 atm L/mol/K

T is the temperature, 112 + 273.15 = 385.15 K

Therefore;

n = PV/RT

n = (4.58 × 13)/(0.0821×385.15)

  = 1.883 moles

The mass will be;

 = 1.883 moles × 46.0 g/mol

 = 86.57 g

 = 86.5 g

the ratio of the conjugate base to the acid required to attain the desired ph.