Chemistry, 31.01.2020 19:57 kimlyn58p0wyn0
Asolution is made by adding 50.0 ml of 0.200 m acetic acid (ka = 1.8 x 10–5) to 50.0 ml of 1.00 x 10–3m hcl. (a) calculate the ph of the solution.
Answers: 2
,
is the concentration of the solute,
is the number of moles of the solute, and
is the volume of the solution.
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.![\displaystyle K_a = \frac{[\text{CH}_3\text{COO}^{-}\;(aq)]\cdot[\text{H}^{+}\;(aq)]}{[\text{CH}_3\text{COOH}\;(aq)]} = \frac{x\cdot(x + 5.00\times 10^{-4})}{0.100 - x}](/tpl/images/0490/9938/f60d8.png)
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.![[\text{H}^{+}\;(aq)] = 5.00\times 10^{-4}\;\text{M} + x\;\text{M} = 0.00161\;\text{M}](/tpl/images/0490/9938/8318a.png)
.![\text{pH} = -\log{[\text{H}^{+}]} = 2.79](/tpl/images/0490/9938/6dac0.png)
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Asolution is made by adding 50.0 ml of 0.200 m acetic acid (ka = 1.8 x 10–5) to 50.0 ml of 1.00 x 10...
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