If 25.21 ml of naoh sloution is required to react completed with .550 g khp, what is the molarity of the naoh solution

= 0.107 M or 0.107 mol/Liter

Explanation:

The molar mass of KHP is 204.22 g/mol

Therefore;

Moles of KHP = 0.550 g/204.22 g/mol

                      = 0.00269 moles

But, there is an equivalence of 1 : 1 between moles of KHP and moles of NaOH.

Hence; Moles of NaOH is 0.00269 moles

But; Molarity or concentration = Number of moles /Volume in Liters

                                                  = 0.00269 moles/ 0.02521 L

                                                   = 0.107 M or 0.107 mol/L