Aquantity of co gas occupies a volume of 0.32 l at 0.90 atm and 323 k . the pressure of the gas is lowered and its temperature is raised until its volume is 3.8 l . find the density of the co under the new conditions. express your answer to two significant figures and include the appropriate units.

Mathematical formula of Ideal Gas Law is PV=nRT
  where: P-pressure, 
              V-volume
              n-number of moles; m/MW
              T-Temperature
              m-mass
              d-density ; m/V
              MW-Molecular Weight
              R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol
    
Substituting the definitions to the original Gas equation becomes:
     d= P x MW / (RxT)

Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K  x 323 K
           
                d = 25.2 g / 26000 mL

                d = .0.00096 g/mL is the density of CO under the new conditions
           

The answer is b because a,c,and d are opinons