The temperature of an ice and water mixture at 1 standard atmosphere remains at 0 c as long as both ice and liquid water are present, no matter what the surrounding temperature

Ithink it’s carbon dioxide

D. product because it is the direct outcome of the process

The rules are different for multiplication and addition, but the least precise value always restricts the answer. first do the multiplication (as per standard order of operations): 24.6681 × 2.38 ≈ 58.7 since 2.38 has the fewest significant figures, it is considered the lease precise value then do the addition: 58.7 + 332.58 ≈ 391.3 since 58.7 has fewest figures right of decimal it is considered least precise. so final answer: 391.3 with four significant figures.

for left side: 3 c, 8 h, 2 o. for right side, 1 c, 3 o, 2 hwe want to balance oxygen last because it is the only one that is isolated. we can fine tune it at the end.put a coefficient on right side to balance the number of carbons.now make the number of hydrogens eventhere are 8 h on the left and 2 h on the right. put a coefficient on the right side like so: now we have 10 oxygens on the right and 2 on the left. to get the left side to have 10 oxygens, put a coefficient of 5 (5 * 2 = 10)the coefficient in front of  in the balanced equation is 3.