When 12.0 grams of ammonia and enough copper(ii) oxide react form: how many grams of nitrogen gas will be formed?

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

wher is the rest of the question

metric time was an attempt to create a standard unit of time based off of 10, but it never took off an is not included in the metric system (si)