An element of atomic number 88 decays radioactively to anelement of atomic number 82.which of the following emissions achieve this result? one alpha particle and one beta particlethree alpha particlesone alpha particlesix beta particles

six beta particles

Explanation:

The atom must have undergone a beta decay. The beta particle it emits would be a positron. A positron resembles an electron but it is positively charged.

A positron has no mass number. It has an atomic number of 1:

⁰₁β is a representation of a positron

When the radioactive element, say X decays by emitting 6 positrons, the atomic number changes to 82 as shown by the element A

₈₈X → ₈₂A + 6⁰₁β + Energy

This obey equation obeys the law of conservation of matter.

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.

the correct answer to this question is 2