Chemistry, 23.11.2019 10:31 Roselyn0131
In a solution of pure water, the dissociation of water can be expressed by the following: h2o(l) + h2o(l) ⇌ h3o+(aq) + oh−(aq) the equilibrium constant for the ionization of water, kw, is called the ion-product of water. in pure water at 25 °c, kw has a value of 1.0 × 10−14. the dissociation of water gives one h3o+ ion and one oh− ion and thus their concentrations are equal. the concentration of each is 1.0 × 10−7 m. kw = [h3o+][oh−] kw = (1.0 × 10-7)(1.0 × 10-7) = 1.0 × 10-14 [h3o+][oh−] = 1.0 × 10-14 a solution has a [oh−] = 3.4 × 10−5 m at 25 °c. what is the [h3o+] of the solution? answer 2.9 × 10−9 m 2.9 × 10−15 m 3.4 × 109 m 2.9 × 10−10 m i don't know yet
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Chemistry, 22.06.2019 03:00
Compare the valence electron configuration of the nobles gas elements seen here. what statement is correct?
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Chemistry, 22.06.2019 14:30
Select all of the statements which are true. electrons are located in shells or orbits around the atom. electrons orbit slowly around the atom. electrons travel in one flat path around the nucleus of an atom. the valence of an atom is determined by the number of electrons in the atom's outermost shell.
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Chemistry, 22.06.2019 14:30
Need ! asap will mark 10 pts using the room temperature line (orange line) and your periodic table, make lists that identify the state of matter (gas, liquid, or solid) in which each element you plotted exists at room temperature. explain your answers
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In a solution of pure water, the dissociation of water can be expressed by the following: h2o(l) +...
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