In the reaction of sodium with bromine, explain which atom is reduced.

i need you to show all the steps because i don't understand.

The reduced atom is Br.

Explanation:

The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent). The oxidation process is the process in which electrons are lost and produce positively charged ions. The reduction process is the process in which electrons is gained and negatively charge ions are produced. In the reaction of chlorine with calcium:

2Na + Br₂ → 2NaBr,

Na loses 1 electrons and is oxidized to Na⁺. (Na → Na⁺ + e).

Br₂ gains 2 electrons and is reduced to 2Br⁻. (Br₂ + 2e → 2Br⁻).

So, the reduced atom is Br.

60.0 - there are 3 significant numbers