8g of aqueous sodium hydroxide reacts with 4g of aqueous aluminum chloride to produce aqueous sodium chloride and solid aluminum hydroxide. balance the equation and give the limiting and excess reactants.

The limiting reactant is AlCl₃ and the excess reactant is NaOH.

Explanation:

3NaOH(aq) + AlCl₃(aq) → 3NaCl(aq) + Al(OH)₃(s)↓,

It is clear that 3.0 moles of NaOH(aq) react with 1.0 mole of AlCl₃(aq) to produce 3.0 moles of NaCl(aq) and 1.0 mole of Al(OH)₃(s).

no. of moles of NaOH = mass/molar mass = (8.0 g)/(40.0 g/mol) = 0.2 mol.

no. of moles of AlCl₃ = mass/molar mass = (4.0 g)/(133.34 g/mol) = 0.03 mol.

∴ 0.09 mol of NaOH (the remaining 1.1 mol is in excess) reacts completely with 0.03 mol of AlCl₃.

the limiting reactant is AlCl₃ and the excess reactant is NaOH.

organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.