Acontainer is filled with neon gas. it has a volume of 1.5l and a pressure of 101.3 kpa. if the volume of the container is increased to 4.00l without removing any of the gas or changing the temperature, what will the new pressure be? ed question

37.98 kPa.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

(P₁V₁) = (P₂V₂)

P₁ = 101.3 kPa, V₁ = 1.5 L,

P₂ = ??? kPa, V₂ = 4.0 L.

(P₁V₁) = (P₂V₂)

∴ P₂ = (P₁V₁)/V₂ = (101.3 kPa)(1.5 L)/(4.0 L) = 37.98 kPa.

it's c (engineer's do their work with mechanical stuff not on any living being)

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