Balance the following equation; then determine how many grams of co2 will be produced when 40.0 mol of co reacts with fe2o3.

(s) + (g) —> (l) + (g)

 Fe2O3      +       3CO >    2Fe    +      CO2

      1           :          3         :            2      :         3

   13.3       <---     40    > 26.6      --->     40    ( mol)

n = m/M

m CO2 = n.M = 13.3  .    40   =  532 ( g)

p/s : i hope that this will help  ( cause i'm not really good at english :}}} )

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante