How many grams are there in 5.0×1024 formula units of ammonia

141.1g

Explanation:

The formula of ammonia is written as NH₃

Given parameters:

Number of particles = 5.0 x 10²⁴atoms

To calculate the mass of the substances that makes up this number of ammonia particles, we follow use the mole concept to derive it.

1. We know that a mole is the amount of a substance that contains the Avogadro's number of particles i.e 6.02 x 10²³

From this, we can then derive the number of moles using the expression below:

Number of moles =

number of particles/6.02 x 10²³

2. With the number of moles, we can deterime the mass using the expression below:

Number of moles= mass/molar mass

Mass(g) = number of moles x molar mass

Solution

From step 1:

Number of moles = 5.0 x 10²⁴ / 6.02 x 10²³

No of moles of NH₃ = 0.83 x 10 = 8.3mol

Step 2:

Molar mass of NH₃:

Atomic mass of N = 14gmol⁻¹

H = 1gmol⁻¹

Molar mass = 14 + (1x3) = 17gmol⁻¹

Using the expression:

Mass(g) = number of moles x molar mass

Mass of NH₃ = 8.3 x 17 = 141.1g

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