The molecular weight of glucose, \text{c}_6 \text h_{12} \text o_6c 6 h 12 o 6 c, start subscript, 6, end subscript, h, start subscript, 12, end subscript, o, start subscript, 6, end subscript, is 180.16\,\dfrac{\text g}{\text{mol}}180.16 molg 180, point, 16, space, start fraction, g, divided by, m, o, l, end fraction. how many moles of glucose are in 19.1\,\text g19.1g19, point, 1, space, g of glucose? express the answer using 3 significant figures. \text{mol}mol

Explanation:

1) Data:

a) Chemical formula: C₆H₁₂O₆

b) Molecular weight, MM = 180.16 g/mol

c) mass, m = 19.1 g

c) n = ?

2) Formula:

3) Soltuion:

Substitute the data:

The significant figures start with the first non-zero digit after the decimal point, so they are 1, 0, and 6, i.e. three significant figures.

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons

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