Chemistry, 13.10.2019 18:50 alyxkellar06

How many moles of nitrogen we have at a temperature of 30 ºc, a pressure of 4.0 atm, and a volume of 4000.ml?

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Answer from: itaheart101

0.64318246684 moles

Explanation:

PV=nRT

(4 atm)(4 L)=n(0.0821)(303 K)

n=0.64318246684

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

Answer from: Quest

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How many moles of nitrogen we have at a temperature of 30 ºc, a pressure of 4.0 atm, and a volume of...