How many moles of co2 are there in a 50.0 dm3 sample of the gas at a pressure of 100.0 kpa and a temperature of 50°c?

609 mol

Explanation:

1) Data:

a) n = ?

b) V = 50.0 dm³ = 50.0 liter

c) p = 100.0 kPa

d) T = 50 °C

2) Physical law:

Ideal gas law: pV = nRT,

3) Constants:

R = 0.08206 atm-liter / K-mol

4) Unit conversions:

T = 50 + 273.15 K = 323.15 KP = 100.0 kPa × (1 amt  /101,325 kPa) = 0.9869 atm

5) Solution:

pV = nRT ⇒ n = pV / (RT)n = 0.9869 atm × 50.0 liter / (0.08206 atm-liter /K-mol × 323.15 K)n = 609 mol ← answer