Percent iron in a mixture that is 52.2% fe2o3

36.51%.

Explanation:

First find the percentage of iron in pure Fe2O3 using the  atomic masses of the elements:

=  (2 * 55.845) * 100 /  (2*55.845+ 3*15.999)

=  69.94 %.

So the percentage of iron in the mixture

=  52.2 * 0.6994

= 36.51 (answer).

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

a polar bond is formed when electrons are shared unevenly between atoms