An ethylene gas torch requires 3200l of gas at 3.0 atm. what will be the pressure of the gas if the ethylene is supplied by a 250.0l tank?

38.4 atm.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(P₁V₁) = (P₂V₂).

P₁ = 3.0 atm, V₁ = 3200 L,

P₂ = ??? atm, V₂ = 250.0 L.

∴ P₂ = (P₁V₁)/(V₂) = (3.0 atm)(3200 L)/(250.0 L) = 38.4 atm.

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