You place a balloon in a closed chamber at stp. you increase the chamber pressure by a factor of 10. what happens to the balloon?

Answer : The temperature of balloon increases to 10 times of original temperature.

Explanation :

In this problem, volume remain constant. The temperature and pressure will vary.

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

or,

where,

= let initial pressure = x

= final pressure = 10x

= initial temperature

= final temperature

Now put all the given values in the above equation, we get:

From this we conclude that, the temperature increases to 10 times of original temperature.

Hence, the temperature of balloon increases to 10 times of original temperature.

3

explanation:

well in order to answer this question you have to provide more information < 3