An automobile tire at 30°c has a pressure of 3.00 atm. temperature decreases to -5°c. assume that there is no volume change in the tire. what is the new pressure of the tire after the temperature change? ? atm

2.65 atm.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(P₁T₂) = (P₂T₁).

P₁ = 3.0 atm, T₁ = 30°C + 273 = 303 K,

P₂ = ??? atm, T₂ = -5°C + 273 = 268 K.

∴ P₂ = (P₁T₂)/(T₁) = (3.0 atm)(268 K)/(303 K) = 2.65 atm.

oh it is true if thats what you are asking