How many moles of calcium chloride (cacl2) are needed to react completely with 6.2 moles of silver nitrate (agno3)? 2agno3 + cacl2 → 2agcl + ca(no3)2

The no. of moles of CaCl₂ are needed = 3.1 mol.

Explanation:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂,

It is clear that 2 mol of AgNO₃ react with 1 mol of CaCl₂ to produce 2 mol of AgCl and 1 mol of Ca(NO₃)₂.

Using cross multiplication:

2 mol of AgNO₃ need  → 1 mol of CaCl₂ to react completely, from stichiometry.

6.2 mol of AgNO₃ need  → ??? mol of CaCl₂ to react completely.

∴ The no. of moles of CaCl₂ are needed = (1 mol)(6.2 mol)/(2 mol) = 3.1 mol.

it is a good conductor

explanation:

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