If 89.6 joules of heat 20.0 grams of iron from 30.0 c to 40.0 c, what is the specific heat of the iron in j/g. c?

H = m c ΔT  

89.6 J = (20.0 g) × c × (40.0 - 30.0)°C  

Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)

the millers tale is the answer.

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.