A75.0-liter canister contains 15.82 moles of argon at a pressure of 546.8 kilopascals. what is the temperature of the canister?

Explanation:

1) Data:

a) V = 75.0 liter

b) n = 15.82 mol

c) p = 546.8 kPa

d) T = ?

2) Formula:

Where:

3) Solution:

a) Solve the equation for T:

b) Substitute and compute:

(since the volume is expressed with 3 significant figures, the answer must show also 3 significant figures)

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