If aluminum is the limiting reactant, some/none/all of it will still be visible after the reaction completes. if cucl2 is the limiting reactant, some/none/all of the aluminum will still be visible.

If aluminum is the limiting reactant, NONE of it will still be visible after the reaction completes.

If CuCl2 is the limiting reactant, SOME of the aluminum will still be visible.

Explanation:

So,

If aluminum is the limiting reactant, NONE of it will still be visible after the reaction completes.

and,

If CuCl2 is the limiting reactant, SOME of the aluminum will still be visible.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :