12. which of these would you expect to be soluble in the nonpolar solvent hexane, c6h14? a h2o b. ch, c naci d sns,

B. CH₄

Explanation:

The primary rule in deciding solubilities is, Like dissolves like. That is,

C₆H₁₄ is a nonpolar solvent. Its strongest intermolecular forces are London dispersion forces.

CH₄ is a nonpolar solute. It contains only nonpolar C-H bonds, and its strongest intermolecular forces are London dispersion forces.

Molecules of the two compounds can easily intermingle with each other because the attractive forces between them are so small.

A is wrong. H₂O is a highly polar substance. Its molecules are so strongly attracted to each other that they will not dissolve in the C₆H₁₄.

C and D are wrong. Both NaCl and SnS are compounds of a metal and a nonmetal. We would predict them to be ionic solids, at the extreme end of polarity. They  will not dissolve in C₆H₁₄.

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