Apan containing 30 grams of water was allowed to cool from a temperature of 90.0 °c. if the amount of heat released is 1,500 joules, what is the approximate final temperature of the water? a. 76 °c b. 78 °c c. 81 °c d. 82 °c

B. 78 °C.

Explanation:

Q = m.c.ΔT,

where, Q is the amount of heat released from water (Q = - 1500 J).

m is the mass of water (m = 30.0 g).

c is the specific heat capacity of water (c = 4.18 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 90.0 °C).

∴ (- 1500 J) = (30.0 g)(4.18 J/g.°C)(final T - 90.0 °C)

∴ (final T - 90.0 °C) = (- 1500 J)/(30.0 g)(4.18 J/g.°C) = - 11.96°C.

∴ final T = 90.0 °C - 11.96°C = 78.04°C ≅ 78 °C.

So, the right choice is: B. 78 °C.

one negative thing it that it can kill water animals. another negative thing is it can cause the destruction of ecosystem. one way water pollution can be reduced is to conserve energy.