Aballoon is filled with a gas to a certain volume at a certain pressure at 0.987°c. if the pressure exerted on the balloon is doubled, what must the temperature (in °c) be to keep the balloon inflated at the same volume?

The temperature (in °C)  to keep the balloon inflated at the given volume is  275. °C.

What is temperature?

Temperature is a measurement of degree that tells the coldness or hotness of any substance.

Given,

Temperature =0.987°C

converted into kelvin -0.987 + 273.15 K = 274.137 K

By Gay-Lussac's law

The pressure and temperature of the gases are in direct proportion at constant volume.

Converting kelvin to Celsius:

548.274 - 273.15 = 275.124 °C

Thus, the temperature is  275. °C.

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275. °C

Explanation:

1) Data:

a) Constant volume

b) Initial pressure: P₀

c) Intitial temperature: T₀ = 0.987°C = 0.987 + 273.15 K = 274.137 K

d) Final pressure: P₁ = 2 P₀

e) Final temperature: unknown, T₁

2) Applied principles:

Gay - Lussac's law: at constant volume, the pressure and temperature of the gases are in direct proportion:

        ⇒ P / T = constante ⇒ P₁ / T₁ = P₀ / T₀

3) Solution:

a) Solve for T₁

T₁ = P₁ T₀ / P₀

b) Substitute the data:

T₁ = 2P₀ × 274.137 K / P₀ = 548.274 K

c) Converto to °C:

T₁ = 548.274 - 273.15 = 275.124 °C ≈ 275. °C (three significant figures)

They can measure  the amount of energy gained or lost

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