Will give brainliest to best answer need it fast! +70 points a 50.0-ml sample of gas is cooled from 119ºc to 80.0ºc. if the pressure remains constant, what is the final volume of the gas?

45.03 mL.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(V₁T₂) = (V₂T₁).

V₁ = 50.0 mL, T₁ = 119ºC + 273 = 392 K,

V₂ = ??? mL, T₂ = 80ºC + 273 = 353 K.

∴ V₂ = (V₁T₂)/(T₁) = (50.0 mL)(353 K)/(392 K) = 45.03 mL.

i just got this problem. it's 90.3

your answer would be a. 12.5 kg