Jason combines the two intermediate steps shown. na(g)+o2(g) -> 2no(g) 2no(g)+o2(g) 2no2(g) which best describes what jason should do with the oxygen molecules? place two of them as products. place two of them as reactants. cancel them out because there is one in each equation. double them because there is one in each equation.

Place two of them as reactants.

Explanation:

1) N₂(g ) + O₂(g) → 2NO(g).

2) 2NO(g )+ O₂(g) → 2NO₂(g).

N₂(g ) + 2O₂(g) → 2NO₂(g).

NO is cancelled out because there is one in each equation in the products side in eq. 1 and in oriduct side in eq. 2.

So, we place two of oxygen as reactants.

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