Chemistry, 17.01.2020 02:31 tommyaberman

The henry's law constant (kh) for o2 in water at 20°c is 1.28 × 10−3 mol/(l·atm). (a) how many grams of o2 will dissolve in 4.00 l of h2o that is in contact with pure o2 at 1.00 atm? g o2 (b) how many grams of o2 will dissolve in 4.00 l of h2o that is in contact with air where the partial pressure of o2 is 0.209 atm?

Answers: 2

Show answers

Answers

Answer from: destiny2521

0.164 grams of oxygen gas was dissolved in 4.00 Liters of water.

0.0343 grams of oxygen gas was dissolved in 4.00 Liters of water.

Explanation:

Henry's law states that the solubility of a gas in a given volume of a liquid is directly proportional to the partial pressure of that gas above the liquid.

$S=k_H\times p_o$

Where:

S = Solubility of gas in liquid

k_H = Henry's law constant

p_o = Partial pressure of a gas

Given:

The Henry's law constant for oxygen gas in water at 20°C is $1.28 \times 10^{-3} mol/(Latm)$

To find:

a) Mass of oxygen gas in 4.00 Liter of water with pure oxygen at 1.00 atm.

b) Mass of oxygen gas in 4.00 Liter of water with oxygen gas at a partial pressure of 0.209 atm.

Solution:

The Henry's law constant for oxygen gas in water at 20°C = k_H = $1.28 \times 10^{-3} mol/(Latm)$

The pressure of pure oxygen gas above water = p_o=1.00 atm

The solubility of the oxygen gas in water:

$S=1.28\times 10^{-3} mol/(Latm)\times 1.00 atm\\S=1.28\times 10^{-3} mol/L$

There are $1.28\times 10^{-3}$ moles of oxygen gas in 1 liter of water

The volume of the water = 4.00 L

Moles of oxygen gas in 4.00 L of water:

$=1.28\times 10^{-3}\times 4.00 mol=5.12\times 10^{-3}mol$

Mass of $5.12\times 10^{-3}$ moles of oxygen gas:

$=5.12\times 10^{-3}mol\times 31.998 g/mol=0.164 g$

0.164 grams of oxygen gas was dissolved in 4.00 Liters of water.

The Henry's law constant for oxygen gas in water at 20°C = k_H = $1.28 \times 10^{-3} mol/(Latm)$

The partial pressure of oxygen gas above water = p_o=0.209atm

The solubility of the oxygen gas in water:

$S=1.28\times 10^{-3} mol/(Latm)\times 0.209atm\\S=2.68\times 10^{-4} mol/L$

There are $2.68\times 10^{-4}$ moles of oxygen gas in 1 liter of water

The volume of the water = 4.00 L

Moles of oxygen gas in 4.00 L of water:

$=2.68\times 10^{-4}\times 4.00 mol=1.072\times 10^{-3}mol$

Mass of $1.072\times 10^{-3}$ moles of oxygen gas:

$=1.072\times 10^{-3}mol\times 31.998 g/mol=0.0343g$

0.0343 grams of oxygen gas was dissolved in 4.00 Liters of water.

Learn more about Henry's law here:

link

Answer from: savannah19dw

Solubility of O₂(g) in 4L water = 3.42 x 10⁻² grams O₂(g)

Explanation:

Graham's Law => Solubility(S) ∝ Applied Pressure(P) => S =k·P

Given P = 0.209Atm & k = 1.28 x 10⁻³mol/L·Atm

=> S = k·P = (1.28 x 10⁻³ mole/L·Atm)0.209Atm = 2.68 x 10⁻³ mol O₂/L water.

∴Solubility of O₂(g) in 4L water at 0.209Atm = (2.68 x 10⁻³mole O₂(g)/L)(4L)(32 g O₂(g)/mol O₂(g)) = 3.45 x 10⁻² grams O₂(g) in 4L water.

Answer from: Quest

football

explanation:

because it is

Answer from: Quest

Is there a picture or answer choices?

Another question on Chemistry

Chemistry, 21.06.2019 13:00

What is the ph of a solution with a 1.50 × 10−9 m hydroxide ion concentration?

Answers: 3

Answer

Chemistry, 23.06.2019 00:30

You are attempting to recrystallize a crude product mixture. you add the appropriate amount of hot solvent and are allowing the solution to slowly cool to room temperature. however, at room temperature no crystals have appeared, which of the following methods should be used to induce crystallization? choose all correct answers. a) place the flask in an ice bath. b) swirl the contents of the flask. c) add a small seed crystal of the desired product. d) scratch the inside of the glassware using a stir rod. it can be multiple choices

Answers: 3

Answer

Chemistry, 23.06.2019 07:00

How does science use models to gain a better understanding of concepts?

Answers: 1

Answer

Chemistry, 23.06.2019 15:30

Light travels through space at 186,282 miles per second and it takes about 1.3 seconds for light to travel from the moon to earth. which of the following is the correct method of finding the distance, in miles, between the moon and earth? add 186,282 and 1.3 divide 186,282 by 1.3 multiply 186,282 by 1.3 subtract 1.3 from 186,282

Answers: 1

Answer

You know the right answer?

The henry's law constant (kh) for o2 in water at 20°c is 1.28 × 10−3 mol/(l·atm). (a) how many grams...

Questions