What is the volume of 3.2 moles of chlorine gas (cl2) at 295 k and 1.1 atm?

Explanation:

We can use the Ideal Gas Law to solve this problem

pV = nRT

Data:

p = 1.1 atm

n = 3.2 mol

R = 0.082 16 L·atm·K⁻¹mol⁻¹

T = 295 K

Calculation:

give me abc and i will get it for u.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.