Given the following information: mass of proton = 1.00728 amu mass of neutron = 1.00866 amu mass of electron = 5.486 × 10^-4 amu speed of light = 2.9979 × 10^8 m/s calculate the nuclear binding energy (absolute value) of 3li^6. which has an atomic mass of 6.015126 amu. j/mol.

The nuclear binding energy of the given element is

Explanation:

For the given element

Number of protons = 3

Number of neutrons = (6 - 3) = 3

We are given:

M = mass of nucleus =

Calculating mass defect of the nucleus:

Converting this quantity into kg/mol, we use the conversion factor:

1 kg = 1000 g

So,  

To calculate the nuclear binding energy, we use Einstein equation, which is:

where,

E = Nuclear binding energy = ? J/mol

= Mass defect =

c = Speed of light =

Putting values in above equation, we get:

Hence, the nuclear binding energy of the given element is