How many moles of gas are present if p=11 atm, v=12l, t=185k?

8.69 mol.

Explanation:

where, P is the pressure of the gas in atm (P = 11.0 atm).

V is the volume of the gas in L (V = 12.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 185.0 K).

∴ n = PV/RT = (11.0 atm)(12.0 L)/(0.0821 L.atm/mol.K)(185.0 K) = 8.69 mol.

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'

it is the most commonly accepted one