What is the composition, in atom percent, of an alloy that consists of 4.5 wt% pb and 95.5 wt% sn? the atomic weights for pb and sn are 207.19 g/mol and 118.71 g/mol, respectively.(a) 2.6 at% pb and 97.4 at% sn(b) 7.6 at% pb and 92.4 at% sn(c)97.4 at% pb and 2.6 at% sn(d) 92.4 at% pb and 7.6 at% sn

The correct answer is Option A.

Explanation:

We are given:

4.5 wt % of Pb means that 4.5 grams of lead is present in 100 g of alloy.

95.5 wt % of Sn means that 95.5 grams of tin is present in 100 g of alloy.

To calculate the atom percent of any compound in a mixture, we use the equation:

where,

= Avogadro's number

Moles of a compound is given by the formula:

Given mass of lead = 4.5 g

Molar mass of lead = 207.19 g/mol

Given mass of tin = 95.5 g

Molar mass of tin = 118.71 g/mol

Hence, the correct answer is Option A.

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