Amonoprotic acid is an acid that donates a single proton to the solution. suppose you have 0.140 g of a monoprotic acid dissolved in 35.0 ml of water. this solution is then neutralized with 14.5 ml of 0.110 m naoh. what is the molar mass of the acid?

molar mass HA = 87.8 g/mole

Explanation:

Given 0.140g HA + 14.5ml(0.110M NaOH) => NaA + H₂O

Rxn is a 1:1 rxn ration => moles HA neutralized = moles NaOH used

=> 0.140g/molar mass of HA = (0.110M)(0.0145L)

=> molar mass of HA = (0.140g)/[(0.110moles/L)(0.0145L)] = 87.8 g/mole

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

58750.08068 is the answer i think